-7/3(x)^2+2x+8=10

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Solution for -7/3(x)^2+2x+8=10 equation: 



-7/3(x)^2+2x+8=10

We move all terms to the left:

-7/3(x)^2+2x+8-(10)=0



Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

2x-7/3x^2-2=0

We multiply all the terms by the denominator


2x*3x^2-2*3x^2-7=0

Wy multiply elements

6x^3-6x^2-7=0

We do not support expression: x^3

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